OpenFileDialog 类型名和文件名冲突,类无法使用

    xiaoxiao2021-12-14  16

    由于将项目名命名为OpenFileDialog,与类型名OpenFileDialog发生冲突,在用到OpenFileDialog时报错:OpenFileDialog是命名空间,此处却当做类型来使用,

    private void button1_Click(object sender, EventArgs e) { OpenFileDialog FileDialog = new OpenFileDialog(); }

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