给定一个数将其转换为二进制（均用字符串表示），如果这个数的小数部分不能在 32 个字符之内来精确地表示，则返回 "ERROR"。
您在真实的面试中是否遇到过这个题？ Yes 样例n = "3.72", 返回 "ERROR".
n = "3.5", 返回 "11.1".
标签 相关题目 很明显就是将整数小数部分拆分，然后分别求出2进制整数部分2进制：%2，向右移动一位循环小数部分2进制：和1比较，向左移动一位public class Solution { /** * @param n: * Given a decimal number that is passed in as a string * @return: A string */ public String binaryRepresentation(String n) { // write your code here String result = ""; if (n == null || n.length() == 0) { return result; } String spilt[] = n.split("\\."); if (spilt.length == 1) { result = binaryInteger(new Integer(spilt[0])); } else if (spilt.length == 2) { String floatBinary = binaryFloat(new Double("0." + spilt[1])); if (floatBinary.equals("ERROR")) { result = "ERROR"; } else if ("".equals(floatBinary) || "0".equals(floatBinary)) { result = binaryInteger(new Integer(spilt[0])); } else { result = binaryInteger(new Integer(spilt[0])) + "." + floatBinary; } } return result; } public String binaryInteger(Integer num) { String result = ""; if (num <= 0) { result = "0"; return result; } while (num > 0) { result = num % 2 + result; num = num / 2; } return result; } public String binaryFloat(double num) { String result = ""; if (num >= 1 || num < 0) { return result; } if (num == 0) { result = "0"; return result; } while (num>0) { if (result.length() > 32) { result = "ERROR"; break; } num = num * 2; if (num >= 1) { result += "1"; num -= 1; } else { result += "0"; } } return result; } }