算法-Array

    xiaoxiao2021-12-14  21

    Array

    Difficulty:Easy

    414. Third Maximum Number          

    Given a non-empty array of integers, return the third maximum number in this array. If it does not exist, return the maximum number. The time complexity must be in O(n).

    Example 1:

    Input: [3, 2, 1] Output: 1 Explanation: The third maximum is 1.

    Example 2:

    Input: [1, 2] Output: 2 Explanation: The third maximum does not exist, so the maximum (2) is returned instead.

    Example 3:

    Input: [2, 2, 3, 1] Output: 1 Explanation: Note that the third maximum here means the third maximum distinct number. Both numbers with value 2 are both considered as second maximum.

    public class Solution { public final int N = 3; public int thirdMax(int[] nums) { if (nums.length == 0) return 0; TreeSet set = new TreeSet (); for (int i = 0; i < nums.length; i++) { if (set.contains(nums[i])) continue; if (set.size() < N || nums[i] > set.first()) { if (set.size() == N) set.remove(set.first()); set.add(nums[i]); } } return set.size() == N ? set.first() : set.last(); } } 
    转载请注明原文地址: https://ju.6miu.com/read-970387.html

    最新回复(0)