题目：
给定一个字符串数组strs, 再给定两个字符串str1和str2，返回在strs中str1和str2的最小距离，如果str1和str2为null,或者不再strs中，都返回-1
列如：
strs = {"1","3","3","2","3","1","3"} ,str1 = "1" str2 = "2" 返回2
strs = {"CD"},str1 = "CD",str2="AC" 返回-1
代码实现：
package com.chenyu.string.cn;
public class MinDistance {
public static void main(String[] args) {
String[] ss = {"a", "b", "c", "d", "c", "a", "d"};
int result = minDistance(ss, "a", "d");
System.out.println(result);
}
public static int minDistance(String[] target, String str1, String str2) {
if (target == null || target.length == 0) {
return -1;
}
if (str1 == nu
chen.yu
认证博客专家
博客排名前200
深信服三年半工作经验，目前就职游戏厂商，希望能和大家交流和学习,微信公众号：
编程入门到秃头 或扫描下面二维码
零基础入门进阶人工智能(链接)
转载请注明原文地址: https://ju.6miu.com/read-970636.html
